On Monday 04 November 2002 16:42, Steve Jackson wrote:
> I want to display an address from my database based on an orderid. Where
> am I going wrong? I am still unsure how Php interacts with mySQL but am
> I right in assuming it should be an array?
>
> My code...
>
> function get_shipping_address($address_array)
> {
> $conn = db_connect();
> $orderid = get_order_id($orderid);
> $query = "SELECT * FROM orders WHERE orderid = '$orderid'";
> $row = mysql_fetch_array($query);
You don't need the foreach loop (and in fact you've mixed up its parameters so
it wouldn't work anyway).
> foreach ($address_array as $row)
> {
> $ship_name = $row["ship_name"];
> $ship_address = $row["ship_address"];
> $ship_city = $row["ship_city"];
> $ship_zip = $row["ship_zip"];
> $ship_country = $row["ship_country"];
> }
Just simply:
$ship_name = $row["ship_name"];
$ship_address = $row["ship_address"];
$ship_city = $row["ship_city"];
$ship_zip = $row["ship_zip"];
$ship_country = $row["ship_country"];
Here's how foreach can be used:
foreach ($row as $field_name => $field_value)
{
echo "$field_name contains $field_value<br>";
}
--
Jason Wong -> Gremlins Associates -> www.gremlins.com.hk
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