I am not php expert but why are there two (( after your create table?
-----Original Message-----
From: Markus J�ntti [mailto:janmark@;bodo.kommune.no]
Sent: Wednesday, November 06, 2002 8:34 AM
To: [EMAIL PROTECTED]
Subject: [PHP] New to PHP, and stuck
I'm working myself through Julie C. Meloni's book "PHP" and now I'm stuck at
chapter 12.
My script gives me this error: You have an error in your SQL syntax near
'()' at line 1
even tho I've even tried replacing my own work with the file from the book's
companion-files.
I'd be very happy if someone would take the time to look through this and
tell me what the problem might be. Hard to move forward when I don't
understand this.
Here's the script:
<?
//indicate the database you want to use
$db_name ="testDB";
//connect to database
$connection = @mysql_connect("localhost","john","doe99") or
die(mysql_error());
$db = @mysql_select_db($db_name,$connection) or die(mysql_error());
//start creating the SQL statement
$sql ="CREATE TABLE $_POST[table_name] ((";
//continue the SQL statement for each new field
for ($i =0;$i < count($_POST[field_name]);$i++){
$sql .= $_POST[field_name][$i]."".$_POST[field_type][$i];
if ($_POST [field_length][$i] != "") {
$sql .= "(".$_POST [field_length][$i]."),";
} else {
$sql .= ",";
}
}
//clean up the end of the string
$sql = substr($sql,0,-1);
$sql .= ")";
//execute the query
$result = mysql_query($sql,$connection) or die(mysql_error());
//get a good message for display upon success
if ($result) {
$msg ="<P>".$_POST[table_name]." has been created!</P>";
}
?>
<HTML>
<HEAD>
<TITLE>Create a Database Table:Step 3</TITLE>
</HEAD>
<BODY>
<h1>Adding table to <? echo "$db_name"; ?>...</h1>
<? echo "$msg"; ?>
</BODY>
</HTML>
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