Your code is bogus. You probably want:
$vary[$i] = $y;
And $vary(100) also makes no sense.
Also, why are you looping through the $InputY array and putting all the
values into $vary? Why not just do $vary = $InputY; ?
If it is because you need to renumber the indices, have a look at the
array_values() function.
-Rasmus
On Thu, 7 Nov 2002, Remon Redika wrote:
> Parse error: parse error, unexpected '=' in
> /home/intra/Inventroot/software/savedata.php on line 35
>
> <?php
>
> $vary(100);
> $i = 0;
>
> foreach($InputY as $y){
> $vary($i) = $y; <---------line 35
> $i++;
> }
>
> foreach($Nama_Software as $x){
> $insertq = "Insert into NSoftware (X, Y) values
> ('$InputX','$vary($i)')";
> echo $insertq."<br>";
> mysql_query($insertq);
> $i++;
> }
>
> ?>
> Thank's
>
>
> Jon Haworth writes:
>
> > Hi Remon,
> >
> >> I try this script with php, but i found an Error.
> >
> > It would be helpful if you could show us this error message.
> >
> >> $vary(100);
> >
> > At the very least, you should change this line to
> >
> > $vary = array();
> >
> > Cheers
> > Jon
> >
> > --
> > PHP General Mailing List (http://www.php.net/)
> > To unsubscribe, visit: http://www.php.net/unsub.php
> >
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
