The reason "imagedestroy()" may have not worked for you is that maybe
imagedestroy() is misspelled? If you misspelled it in the code then it won't
work. Just a suggestion.
> -----Original Message-----
> From: Robbert van Andel [mailto:robbert@;vafam.com]
> Sent: Thursday, November 07, 2002 9:30 PM
> To: [EMAIL PROTECTED]
> Subject: [PHP] Graphics question
> I have created a webpage that builds a table and graph using the GD
> functions. When I switch to another page or select a different month to
> build the table for, the graph.jpg does not rebuild. I have to press
> reload to make the graph render using the new data. I have used
> imagedistroy($pic) in the hopes that this will work, but it didn't.
> To elaborate on the situation, I first call imagecreate, then run the
> code to create the bar graph. I then use
> imagejpg($pic,$graphname) (or something ot that affect. I don't have
> access to the code at home).
> I then show the picture using
> echo "<img src=\"$graph\">";
> Finally I call imagedestroy($pic). Do you have any suggestions?
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