try this: $yyyymmdd = "$foo.$bar.$bleh.$doh"; /*note double-quotes and the concat operator (the period) */ $$yyyymmdd = a_date_value;
To test; echo $yyyymmdd ; echo $$yyyymmdd; /*provided that a_date_value is a string literal*/ Robert McPeak <[EMAIL PROTECTED]> wrote in message news:sdcbab6c.044@;ccp2.jhuccp.org... My newbie brain is maxed out on this, and I'm sure one of you more experience guys can quickly straighten me out. I've got a variable: $_yyyymmdd = a_date_value; Later, I've got four variables; $foo= _; $bar=yyyy; $bleh=mm; $doh=dd; I want to stick these variables together on the fly to get "_yyyymmdd " and use that value as a variable name to return "a_date_value". It would be the equivalent of, echo "$foo$bar$bleh$doh"; That would give me "a_date_value" I've read the docs on dynamic variables but still can't seem to break through mentally on this one. Can you clear this up for me? Thanks in advance. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
