"Kevin Stone" <[EMAIL PROTECTED]> wrote:
> I think you're trying to defy logic here. How will the function know that
> you want to keep color=>cherry or flavor=>cherry? What logical construct
> makes that decision? The example you've given will result in an array
that
> looks eactly like $arr1 regardless of the content in either array.
i beg to diff-er (haha, i'm so punny:). the function i wrote works the way
i want it to, but perhaps i neglected to mention that it only works on
purely associative arrays, i.e. string keys only. try this one:
$arr1 = array("name" => "Bing", "color" => "red", "flavor" => "cherry");
$arr2 = array("name" => "Bing", "color" => "cherry", "flavor" => "red");
print_r(myArrayDiff($arr2, $arr1));
output:
Array ( [color] => cherry [flavor] => red )
in words, the difference between arr2 and arr1 is that "color" changed to
"cherry", and "flavor" changed to "red".
/nick
> > function myArrayDiff($thing1, $thing2)
> > {
> > $diff = array();
> > while (list($key, $val) = each($thing1))
> > {
> > if ((string)$val !== (string)$thing2[$key])
> > $diff[$key] = $val;
> > }
> >
> > return $diff;
> > }
> >
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