You don't need the () around print.
print testfunction($var1, $var2, $var3, $var4);
Jason
On Wed, 2002-11-20 at 17:48, Tracy Finifter Rotton wrote:
> Try:
>
> $meat = testfunction ($var1, $var2, $var3, $var4);
> echo $meat;
>
>
> Or, alternatively,
>
> print (testfunction ($var1, $var2, $var3, $var4));
>
>
> hope this helps.
>
> --t
>
> On 11/20/02 8:40 PM, "Beauford 2002" <[EMAIL PROTECTED]> wrote:
>
> > Hi,
> >
> > I have form that a user would input information and that info is sent to
> > a function, but I need to be able to return a result of this function
> > and is where I am having a problem.
> >
> > For example:
> >
> > testfunction($var1, $var2, $var3, $var4); //the form fills these
> > values.
> >
> > echo $meat;
> >
> > function testfunction($a, $b, $c, $d) {
> >
> > The $meat of the function goes here;
> >
> > Now I need to return the result of $meat;
> >
> > return $meat;
> > }
> >
> > This does not work. I'm new to funtions and obviously missing something,
> > but I haven't been able to find a good tutorial on this. The PHP manual
> > isn't much help.
> >
> > Any help is appreciated.
> >
> >
>
> --
> Tracy F. Rotton
> [EMAIL PROTECTED]
> http://www.taupecat.com/
>
> "... I like the 49ers because they're pure of heart,
> Seattle because they've got something to prove,
> and the Raiders because they always cheat."
> -- Lisa Simpson, "Lisa the Greek"
>
>
> --
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