On Thu, 21 Nov 2002, Jason Wong wrote:
> That's because it's expecting a _decimal_ and will automatically convert it to
> hex for you.
AH! Must've been a longer day than I thought ... dunno how that escaped
me. Somehow I was reading "x - the argument is treated as in integer and
presented as a hexadecimal number" as if it meant the function would
recognize the argument as a integer, even though it's in hex format
(resembling a string).
Thanks for clearing that up for me!
~Chris
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