Perhaps the error lies in 

for ($n = 0; $i < count($$pdag); $n++) {

You have $$pdag instead of $$pdag.  You also have it lower down in the code.

Robbert van Andel 

-----Original Message-----
From: -<[ Rene Brehmer ]>- [mailto:[EMAIL PROTECTED]]
Sent: Thursday, November 21, 2002 1:05 PM
Subject: [PHP] echo'ing array contents through reference variable ...
why doesn't this work???

I've run into something I don't understand...

This is my test code:

  $premieredag =
  $d20021122 = array("001");
  $d20021129 = array("002","003","004");
  $d20021206 = array("005","006","007");
  $d20021218 = array("008","009");

  for ($i = 0; $i < count($premieredag); $i++) {
    echo("<td class=\"date\" width=\"15%\">");
    echo date("j. F Y",strtotime($premieredag[$i]));
    echo ("</td><td>&nbsp;</td>\n");
    $pdag = "d".str_replace("-","",$premieredag[$i]);
    for ($n = 0; $i < count($$pdag); $n++) {
      echo("<td colspan=\"2\" class=\"filmtxt\">");

When it runs, it goes beserk, and gives me this:

<td class="date" width="15%">22. November 2002</td><td>&nbsp;</td>
<td colspan="2" class="filmtxt"></td>
<td colspan="2" class="filmtxt"></td>
<td colspan="2" class="filmtxt"></td>
<td colspan="2" class="filmtxt"></td>
<td colspan="2" class="filmtxt"></td>

...and so on ...

It never ends ... and I get no error messages ... 

So I must conclude that count($$pdag) does not work on reference
variables... what can you do about that? The arrays that $$pdag refers to
are variable length (or will be in the final code), so I really need to be
able to do it this way ...

Any other way to find the top of an array ???


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