Adam, I know this.  In reaction to the subject of John's post I cleared up
the fact that x can not be acting as a multiplier becuase it is not an
operator.  My suggestion was that there may something else in his code that
is causing the confusion.. making it look like it's doing something that
it's not actually doing.  Does that make more sense?  :-\

John, please copy and paste the output of the following experiment..

$a = 1;
$b = 2;
echo "$ax$b";
echo $a."x".$b;
echo $a.'x'.$b;

-Kevin

----- Original Message -----
From: "John Meyer" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, December 03, 2002 3:59 PM
Subject: RE: [PHP] "x" as a multiplier


> Exactly.  But it's only giving me one of the numbers without the space
> between the numbers and the x.
>
> -----Original Message-----
> From: Adam Williams [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, December 03, 2002 3:48 PM
> To: Kevin Stone
> Cc: John Meyer; [EMAIL PROTECTED]
> Subject: Re: [PHP] "x" as a multiplier
>
>
> I don't think he's trying to multiply, I think he wants to print #x#, like
> 800x600 or 1024x768, etc...
>
> Adam
>
> On Tue, 3 Dec 2002, Kevin Stone wrote:
>
> > Is it possible you're mistaken somehow?  x isn't an operator in PHP.
> > Executing $a x $b will give you a parse error.  Anything in quotes is
> > automatically casted as a string.
> > -Kevin
> >
> > ----- Original Message -----
> > From: "John Meyer" <[EMAIL PROTECTED]>
> > To: <[EMAIL PROTECTED]>
> > Sent: Tuesday, December 03, 2002 3:20 PM
> > Subject: [PHP] "x" as a multiplier
> >
> >
> > > Code:
> > >
> > > $newwidth . "x"  . $newheight
> > >
> > >
> > > What I want to get out is a string, like 89x115.  All I am getting
> though,
> > > is one number, even though  if I do this
> > >
> > > $newwidth . " x "  . $newheight
> > >
> > > It prints out just fine.  What is going on here?
> > >
> > >
> > > --
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> > >
> > >
> >
> >
> >
> >
>
>
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>



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