When I wanted to output the png to file, I just need to plop the global
label in front of the $image_filename before I passed it.. Simple mistake,
that's what I get for using someone else's script ;-)
// output PNG object.
global $image_filename;
imagePNG($image, $image_filename);
"Jason Wong" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> On Monday 09 December 2002 23:44, Jeremiah Breindel wrote:
> > Ok. I stripped the needed code out of the image creation script and
> > inserted it into my update script. It works great as long as I hard
> > code in the filename of the file that is being saved to the server.
> > When I pass the image creation function a variable for the filename it
> > tells me "invalid filename", although I am echoing it out right before
> > and it looks perfect. Any thoughts?
>
> Could you show the (relevant) parts of your updated code?
>
> --
> Jason Wong -> Gremlins Associates -> www.gremlins.biz
> Open Source Software Systems Integrators
> * Web Design & Hosting * Internet & Intranet Applications Development *
>
> /*
> Put your brain in gear before starting your mouth in motion.
> */
>
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