$sql = "SELECT .....";
$sql_e = mysql_query($sql);
while ($result = mysql_fetch_array($query_e)) {
.....
}
You were missing the mysql_query
<[EMAIL PROTECTED]> escribió en el mensaje
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> I am trying to display a column from my database as a list. Each listing
> needs to be a URL that links to another script that brings up all of the
data
> in the row to edit. I keep getting a parser error and I can't figure it
out.
> Here is the code and any help is greatly appreciated.
>
> <?php
> $db = mysql_connect("localhost", "Uname", "PW");
>
> $select_db = mysql_select_db("machmedi_meetingRequest",$db);
> $sql = "SELECT * FROM requests";
>
> while ($result = mysql_fetch_array($query)) {
> $id= $result["id"];
> $meetingName= $result["meetingName"];
>
> echo ("<a href=\"edit.php?id='$id'\">$meetingName</a><P>");
> ?>
>
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