What do you mean "return to the calling page"?
The exit() command simply ceases processing of PHP and HTML.
I believe what you're saying is that if the user clicks on a PHP hyperlink on the first
page, then goes to another page. If there is something "wrong" there, you nwant to
return
to the page from which you hyper-linked. If that is the scenario, the valriable
$HTTP_REFERER refers to the calling page. So:
if( condition)
header("location: $HTTP_REFERER");
----- Original Message -----
From: "Beauford.2002" <[EMAIL PROTECTED]>
To: "PHP General" <[EMAIL PROTECTED]>
Sent: Thursday, December 19, 2002 3:45 PM
Subject: [PHP] Question about the exit() command
Hi,
Could someone clarify this for me. I want to be able to exit out of a PHP
webpage and return to the calling page if certain conditions are not met. It
appears using exit() will do this, but I am unclear exactly how to use it.
any info is appreciated.
TIA
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