The example doesn't have to make sense, but Im looking for the correct syntax for $foo. I was trying ->
$foo = '\[this\](.*?)that';
$bar = 'the other';

$str = preg_replace($foo, $bar, $other_string);

But that doesn't work. I came across an example where the syntax of $foo is in ->
$foo = '#\[this\](.*?)that#';

The second syntax of $foo works. I was wondering on the meaning of # in the string??

Thanks

--
Gerard Samuel
http://www.trini0.org:81/
http://dev.trini0.org:81/



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