Hi Wade, Try update table set x = 'your value' where id = 'y'
HTH. -Weng ________________________________ From: Wade [mailto:[EMAIL PROTECTED] I have a table that already has a id in it from page one. That is all that is in it. On page two I'm getting other values that will be put in it. However, there is also another table that I will be inserting values in as well. How do I say "INSERT INTO table (x) VALUES (" '".$_POST['y']."') WHERE a = Tom"; Can you do that? Community email addresses: Post message: [email protected] Subscribe: [EMAIL PROTECTED] Unsubscribe: [EMAIL PROTECTED] List owner: [EMAIL PROTECTED] Shortcut URL to this page: http://groups.yahoo.com/group/php-list Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/php-list/ <*> To unsubscribe from this group, send an email to: [EMAIL PROTECTED] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/
