Hi use this code.
<?php
function get_day( $describer, $weekday, $reference_date ) { //$reference_date
format = m-Y
$d = explode('-',$reference_date);
switch ($describer) {
case 'first': $offset = get_day_offset($reference_date, $weekday);
break;
case 'second': $offset = get_day_offset($reference_date, $weekday) + 7;
break;
case 'third': $offset = get_day_offset($reference_date, $weekday) +
14; break;
case 'fourth': $offset = get_day_offset($reference_date, $weekday) +
21; break;
case 'last': $reference_date = ($d[0]+1).'-'.($d[1]); $d =
explode('-',$reference_date);
$offset = get_day_offset($reference_date, $weekday) - 7;
break;
}
$r = mktime( 0, 0, 0, $d[0], 1+$offset, $d[1] );
return $r; //returns timestamp format
}
function get_day_offset( $anchor , $target ) { //$anchor format = m-Y
$ts = explode('-',$anchor);
$ts = mktime(0,0,0,$ts[0],'01',$ts[1]);
$anchor = date("w",$ts);
$target = strtolower($target);
$days = array( 'sunday'=>0, 'monday'=>1, 'tuesday'=>2, 'wednesday'=>3,
'thursday'=>4, 'friday'=>5, 'saturday'=>6 );
$offset = $days[$target] - $anchor;
if ($offset<0) $offset+=7;
return $offset; //returns 0-6 for use in get_day();
}
$date1 = get_day("Second", "Saturday", "12-2007");
$date2 = get_day("Last", "Friday", "11-2007");
$date3 = get_day("Second", "Sunday", "11-2007");
echo "Last Friday of November, 2007: ".date("m-d-Y", $date2)."<br>";
echo "Second Sunday of November, 2007: ".date("m-d-Y", $date3)."<br>";
?>
if any doubts on this code ask me
hope it works
subba reddy
Bob <[EMAIL PROTECTED]> wrote: Hi,
I'm trying to calculate the 2nd Sun in Nov of the current year, using php 4.3
echo date('w', mktime(0,0,0,11,1));
would give me (0 - 6 Sun to Sat) Nov 1st of current year
Not sure whether I'm on the right track, starting this way?
Tried strtotime(); but maybe I was doing something wrong.
Speed is not too important, as it's only called one.
Any advice on how to tackle this?
Thanks, Bob.
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