--- In php-list@yahoogroups.com, <[EMAIL PROTECTED]> wrote:
>
> ----- Original Message -----
> From: "brucewhealton"
>
> Hello all,
> I thought this would be very easy but I'm doing something
> wrong here. I want to create a display of an image using a variable.
> In static html it is
> <img src="images/topbanner1.jpg" />
>
> I want the topbanner to change depending on the month of the year.
> So, I calculate that with this, easy enough:
> <?php
> $monthnum = data("n");
> ?>
>
> I have six banners so I if $monthnum is greater than 6, I subtract 6.
> This so far is very easy.
>
> Now, I want to build up the image tag using the php values. So, I
> have the following (this is just the part of the code for displaying
> the image.
>
> echo "<img src=\"images/topbanner";
> echo $monthnum."jpg";
> echo "\"/>";
>
> I used the \ to escape the " on the first line where it should be
> src="images/topbanner"
>
> What's wrong here?
> Thanks,
> Bruce
> ------------------------------------
>
> $number = 0 + date('n');
> if($number > 6) {$number = $number - 6;}
> echo('<img src="images/topbanner' . $number . '.jpg" />');
>
> you were missing the . before jpg
>
---------------------------------------
Thanks. That works now!
Bruce
