php-windows Digest 20 Feb 2007 02:25:57 -0000 Issue 3144
Topics (messages 27500 through 27501):
Re: A measre of security
27500 by: Gustav Wiberg
27501 by: bedul
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----------------------------------------------------------------------
--- Begin Message ---
-----Original Message-----
From: bedul [mailto:[EMAIL PROTECTED]
Sent: Saturday, February 17, 2007 10:26 AM
To: Gustav Wiberg; [email protected]
Cc: [email protected]
Subject: Re: [PHP-WIN] A measre of security
Importance: High
cmiiw
----- Original Message -----
From: "Gustav Wiberg" <[EMAIL PROTECTED]>
To: <[email protected]>
Sent: Wednesday, February 14, 2007 6:39 PM
Subject: [PHP-WIN] A measre of security
Hi!
This is a kind of security-question....
I'm starting up a system, where several customers should be able to login
with there own information.
Each company I give unique identity with "hard-coding" and each company has
its own folder...
Harding-coding, something like:
$company -> setIDCompany(1);
$company -> setIDCompany(2);
$company -> setIDCompany(3);
[bedul]
you should not try hardcoding by your self.. is suffer your health.. hehehe
why don't you use an id.. if you enter this using db.. every new record or
company will given a new id..
like you enter new comp anda the new will have 4 and soon
but if this not what you wanted.. just created a random var like this
i enter new comp.. where the var given = a4s43.. this comp will have id
a4s43 and have folder named a4s43
=====================================================
Diffrent folders:
customers/company1
customers/company2
customers/company3
and so on...
This isn't complicated, but when I add a new company.... ...I must be
200% sure that the IDCompany is set correct (There is a chance of setting
the wrong ID for a new company or forgetting to change it)
[bedul]
to search what your id entered .. try use
int mysql_insert_id ( [resource link_identifier] )
Retrieves the ID generated for an AUTO_INCREMENT column by the previous
INSERT query.
=======================================
The companys ARE NOT ALLOWED to see each others information.
[bedul]
try above suggestion.. use random var for folder.. how to get em??
$idFromTable=mysql_insert_id ($handle);
$rndNum=rand(2100);
$randomID="a".$idFromTable."s".$rndNum;
========================================
Is there any good way of solving this with some sort of
comparision-mechanism or something like that? Any thoughts?
[bedul]
interesting. can u explain more about 'sort of comparision-mechanism'??
Hi there!
Thanx for your suggestion! What I meant with comparisaion-mechanism was that I
Want to have som kind of fucntion that is "almost" impossible to set ID 1 -
Company 2, impossible to set ID2 for company 1. The function should check
Somehow that the right ID is set.. Like ID 1 = Company1, ID 2 = Company and so
on...
Best Regards
/Gustav Wiberg
--- End Message ---
--- Begin Message ---
----- Original Message -----
From: "Gustav Wiberg" <[EMAIL PROTECTED]>
To: "'bedul'" <[EMAIL PROTECTED]>; <[email protected]>
Cc: <[email protected]>
Sent: Monday, February 19, 2007 2:28 PM
Subject: RE: [PHP-WIN] A measre of security
-----Original Message-----
From: bedul [mailto:[EMAIL PROTECTED]
Sent: Saturday, February 17, 2007 10:26 AM
To: Gustav Wiberg; [email protected]
Cc: [email protected]
Subject: Re: [PHP-WIN] A measre of security
Importance: High
cmiiw
----- Original Message -----
From: "Gustav Wiberg" <[EMAIL PROTECTED]>
To: <[email protected]>
Sent: Wednesday, February 14, 2007 6:39 PM
Subject: [PHP-WIN] A measre of security
Hi!
This is a kind of security-question....
I'm starting up a system, where several customers should be able to login
with there own information.
Each company I give unique identity with "hard-coding" and each company has
its own folder...
Harding-coding, something like:
$company -> setIDCompany(1);
$company -> setIDCompany(2);
$company -> setIDCompany(3);
[bedul]
you should not try hardcoding by your self.. is suffer your health.. hehehe
why don't you use an id.. if you enter this using db.. every new record or
company will given a new id..
like you enter new comp anda the new will have 4 and soon
but if this not what you wanted.. just created a random var like this
i enter new comp.. where the var given = a4s43.. this comp will have id
a4s43 and have folder named a4s43
=====================================================
Diffrent folders:
customers/company1
customers/company2
customers/company3
and so on...
This isn't complicated, but when I add a new company.... ...I must be
200% sure that the IDCompany is set correct (There is a chance of setting
the wrong ID for a new company or forgetting to change it)
[bedul]
to search what your id entered .. try use
int mysql_insert_id ( [resource link_identifier] )
Retrieves the ID generated for an AUTO_INCREMENT column by the previous
INSERT query.
=======================================
The companys ARE NOT ALLOWED to see each others information.
[bedul]
try above suggestion.. use random var for folder.. how to get em??
$idFromTable=mysql_insert_id ($handle);
$rndNum=rand(2100);
$randomID="a".$idFromTable."s".$rndNum;
========================================
Is there any good way of solving this with some sort of
comparision-mechanism or something like that? Any thoughts?
[bedul]
interesting. can u explain more about 'sort of comparision-mechanism'??
Hi there!
Thanx for your suggestion! What I meant with comparisaion-mechanism was that
I
Want to have som kind of fucntion that is "almost" impossible to set ID 1 -
Company 2, impossible to set ID2 for company 1. The function should check
Somehow that the right ID is set.. Like ID 1 = Company1, ID 2 = Company and
so on...
Best Regards
/Gustav Wiberg
[bedul]
i believe u talk about random id?? cmiiw
why not using random by combine ip regis & date regis?
read the 4 line.. i think, u might ask about cookie or session?? i believe
this is more close what u describe above. if this like webhosting.. u might
use share folder but if this not hosting.. i more simple. (yet less simple
actualy from hard coding /omg)
what u say before.. actualy i don't get it? why you have to make share
folder? why not the file put on 1 folder. use database to describe the file
then u probably able to share the file and make folder (it not real folder
actualy.. it is just a database).
fyi search for sharing data aplication. try this link
http://sourceforge.net/projects/simpledirectory
http://sourceforge.net/projects/phpexplorer
http://sourceforge.net/projects/phpshell
http://savannah.nongnu.org/projects/phpexplore/
--- End Message ---
