You can use PHP's date function to do this - information here: http://www.php.net/date In your case the function would be... $yourdate = date("d") . (date("w") + 1) . date("mY"); I'm pretty sure that will work - I had to use a messy construct because the "w" element of the date function returns Sunday as 0 rather than 1 Read up on the PHP date function - it's very powerful and very easy to use Cheers, Simon -----Original Message----- From: Ben Cairns [mailto:[EMAIL PROTECTED]] Sent: 25 January 2001 10:22 To: [EMAIL PROTECTED] Subject: Date + Time I need to get the date, day, month,year from the server that PHP is running on. How can I do this. I need this information to be returned like: 255012001 Explained: The Date (Numerical - 2 Digits) Day (Day Number, Weeks starts on Sunday - Sun=1, Mon=2, Tue=3....) Month (Numerical - 2 Digits) Year (Numerical - 4 digits) but this information has to come from the SERVER as the site visitors will be all over the world, and the date's will be wrong Thanks in advance -- Ben Cairns - Head Of Technical Operations intasept.COM Tel: 01332 365333 Fax: 01332 346010 E-Mail: [EMAIL PROTECTED] Web: http://www.intasept.com "MAKING sense of the INFORMATION TECHNOLOGY age @ WORK......" -- PHP Windows Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
