Hi everyone,
I'm, having trouble with getting PHP4 to run on my win98 machine with Apache
1.3.19. Apache works fine: when I type http://localhost/ I see the Apache
Welcome Page. However, when I try to display a PHPinfo() page, I get the
following error message:
The File PHP.EXE is connected to missing output PHP4TS.DLL-ts_resource
Meanwhile, Apache gives a 500 Internal Server error. The log states it
couldn't spawn a child process. Also, when I double-click on php.exe in
c:\php4\, I get the above error message, as well as the following message:
C:\php4\ a device connected to the system doen's work
(both error messages are translated from dutch, I hope you can make some
sense of it) Could anyone tell me what's going on and advise me how to solve
the problem? More detailed config info can be found below:
the variables I added/changed in php.ini are literally this:
doc_root = C:\program files\apache group\apache\htdocs
extension_dir = C:\php4
the variables I added/changed in Apache's httpd.conf are as follows:
ServerName localhost
ScriptAlias /php4/ "C:/php4/"
AddType application/x-httpd-php .phtml .php
AddType application/x-httpd-php-source .phps
I've changed/ added/ deleted NOTHING else in the above two files
Furthermore, my phpinfo.php file looks like this:
<? phpinfo(); ?>
I also tried the folowing file:
<?php
echo "<P> This is a test using the first tag type.</P>";?>
<? echo "<P>This is a test using the second tag type</P>';?>
<script language="php">
echo "<P> This is a test using the third tag type.</P>";
</script>
Both give the above error message
My php.ini file is in C:\windows\
msvcrt.dll and php4ts.dll are in C:\windows\system\
Any help would be greatly appreciated!
Kind regards,
Paul
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