Hi _lallous,
yes, but I think he knew this already. the question is that since $this
itself is a reference to the object, why inside the class still need to
assign the address of $this to $globalref[]?
--
regards,
chen wei (http://www.cw213.net)
===================================
Solutions Developer of Earth9.com
===================================
Wednesday, September 26, 2001, 6:45:15 PM, you wrote:
_> &$varname menas to take the address of the variable,
_> example:
_> $a = "Hello world!";
_> $b = &$a;
_> $b = "Hi! this is var B";
_> echo $a;
_> // output will be: Hi! this is var B
_> "Ming-Chieh Lee" <[EMAIL PROTECTED]> wrote in message
_> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
>> does anyone know what does &$this mean? I saw this on the php.net
_> tuturial
>> for references inside a constructor.
>> I thought that $this is already a reference?
>> The way it was used :
>> class Foo
>> {
>> function Foo($name)
>> {
>> // create a reference inside the global array $globalref
>> global $globalref;
>> $globalref[] = &$this;
>> // set name to passed value
>> $this->setName($name);
>> // and put it out
>> $this->echoName();
>> }
>> thanks for any input!
>>
>>
>>
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