You may want to add
exit;
where the failures occur to stop code "execution."
> if ( $link = mysql_connect($host,$user,$pswd) )
> {
> if( !mysql_select_db($db, $link) )
> {
> echo "error selecting db";
exit;
> }
> }
> else {
> echo "error connecting to db";
exi;
> }
"Nicole Amashta" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Please try this:
>
> if ( $link = mysql_connect($host,$user,$pswd) )
> {
> if( !mysql_select_db($db, $link) )
> {
> echo "error selecting db";
> }
> }
> else {
> echo "error connecting to db";
> }
>
> Nicole Amashta
> www.aeontrek.com
>
> "Hawk" <[EMAIL PROTECTED]> wrote in message
> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > Having a problem with this, I have a working login that supports
multiple
> > users, and I'm trying to make it possible for the users to change their
> own
> > settings etc, but I get killed when trying to send the data to the MySQL
> > database.
> > To connect I use mysql_connect($host,$user,$pswd) and
mysql_select_db($db)
> >
> > the retrieving data from the form works since I belive, since it showed
up
> > when I added a print "$the vars " but I don't know how to save it to the
> > database..
> >
> > I might be missing some line or maybe it's just because I'm a newbie or
> > something.. ;D
> > anyway.. I use something similiar to this
> > $query = "UPDATE users SET email='$email'"; // and so on..
> > $result = mysql_query($query) or die ("blabla");
> >
> > I don't get any error lines or anything, the only thing that shows is
the
> > "blabla" thing.
> >
> > I also tried INSERT INTO in the query but that didn't make any
difference
> :p
> >
> > if anyone could tell me what I'm doing wrong I would be happy.. :p
> > "the best way to learn is to ask people that know" :p
> >
> > Hawk
> >
> >
>
>
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