Bonjour,
Thanks Sebastian, you put me in the right direction.
I turns out that the newest XSLT API will NOT pass the parameters array when
xslt_process() uses URIs for the XML source and the XSL sheet, like it used to with
the previous versions "xslt_run()". One must use arguments for the XML and XSL content.
In other words:
$xslt_args = array( '/_xml' => $xml, '/_xsl' => $xsl ) ;
$result = xslt_process( $xh, 'arg:/_xml', 'arg:/_xsl', NULL, $xslt_args, $xslt_params
) ==> good
$xslt_args = array() ;
$result = xslt_process( $xh, 'xml_content.xml', 'xsl_sheet.xsl', NULL, $xslt_args,
$xslt_params ) ==> bad
(the transformation works correctly, but parameters are not passed)
Fortunately it did not prove necessary to turn register_globals ON.
Ignatius Reilly
--------------------------------------------------------------------------------
----- Original Message -----
From: Ignatius Reilly
To: [EMAIL PROTECTED]
Sent: Saturday, August 17, 2002 6:10 PM
Subject: Re: [Sab] Problem passing variables with PHP 4.2
Thanks Mattes,
That's in fact what I am doing. My script is conform to the documentation. However,
my <xsl:value-of select="{$VAR_NAME}" /> fills empty string values for the variable.
The really strange thing here is that it used to work with PHP 4.0, but not any more.
Could it be a variable scoping problem? Anything to do with register_globals = off
(in php.ini) ?
I am really puzzled
------------------------------------------------------------------------------
----- Original Message -----
From: Matthes
To: [EMAIL PROTECTED]
Sent: Saturday, August 17, 2002 7:35 PM
Subject: Re: [Sab] Problem passing variables with PHP 4.2
You can call your vars simply by defining <xsl:param name="lang" /> at
the top of your script (after xsl headers but before templates
definitions - see php online documentation, there's some comment
about this) and then access them in your xsl script by calling them
like <xsl:value-of select="{$VAR_NAME}" /> or so.
try this:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="html" indent="yes"/>
<xsl:param name="lang" />
...
<xsl:value-of select="$lang" />
...
it should work ;)
Matthes
IR> Hi,
IR> Since upgrading from PHP 4.0 to 4.2, I do not manage any longer to pass
parameters from the PHP script. The XSLT transformations is performed allright,
though, and use empty values for the
IR> parameters defined.
IR> I tried to kludge by passing parameters in the form of string arguments:
IR> $xslt_args["lang"] = "<a>French</a>" ;
IR> and <xsl:param name="lang" select="document('arg:/lang0')/a"/>
IR> ... but here again I get a 'arg:/lang' not found error
IR> I use Apache 1.3.14 on a W2K machine
IR> Anybody has encountered the same problem?
IR> Ignatius
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