This will work, with several caveats since the purpose is not known.......
<?php
$dir = dir("c:/");
while($filename=$dir->read())
{
if (!is_dir($filename))
{
clearstatcache();
$extension = substr($filename,-4);
$realext = strstr($extension, ".");
if ($realext <> "")
{
echo $realext."<br>\n";
}
}
}
$dir->close();
?>
Output for me looked like this:
.BAT
.ini
.SYS
.sys
.SYS
.SYS
.cnf
.COM
One of the exceptions is that the is_dir function doesn't really seem to
work on windows/IIS. Since this is the only test environment I have, I can
only assume that it does work ok with a linux-based webserver or it wouldn't
be in there. In fact, if I put in is_file() instead of !is_dir, it returns
nothing at all. Anyway, that takes a list of all files and directory names
in the given directory (c:/ - yes it has to be a / not a \ - in my example),
checks to see if it's a directory or a file (theoretically...), then grabs
the last 4 characters that start with a ".", tosses them onto the screen.
Replace the last echo with whatever manipulation you're going for. The
things this will include that it shouldn't: directories with a 3-character
extension. Things it won't include that you might need: files with a
4-character-or-more or a 2-character-or-less extension. It only grabs
3-character extensions. From here, though, I think you can modify it to do
whatever it is you need done.
(V)
----- Original Message -----
From: "Dean Hayes" <[EMAIL PROTECTED]>
> Hey,
>
> I need to be able to find out what the file ext is on all files within the
> dir i am reading. I am searched the php manual and i can not find anything
> that does this does anyone know of a way i can and print it out.
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