I ran an phpinfo check on both servers. On the server
that the subquery works, it says that the Client API
Version is: 3.23.56. On the server that the subquery
DOES NOT work, it says that the Client API Version is:
4.0.25. Is that the version of MySQL that is on the
server? Or is that something else? And if this is not
how the find the version running on the servers, then
how do I find that out?

Again, I'm just learning so forgive me if these are
dumb questions.

Thanks,

Mark 

--- Jim Mullen <[EMAIL PROTECTED]> wrote:

> Mark,
> 
> The servers are two different versions. The one on
> which the query works 
> supports subqueries and the one on which it doesn't
> work does not 
> support subqueries.
> 
> Best regards,
> Jim at iDimensionz.com
> -- 
> http://www.iDimensionz.com Professional web site
> design and affordable 
> web site hosting.
>
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> musicarr34 wrote:
> 
> > Hi,
> >
> > I am in the process of learning PHP/MySQL. This is
> my first post.
> > Below is a snippet of a query (shortened for
> example purposes) that
> > works on my current server, but does not work on
> the server I am in
> > the process of moving to. (Scary). Here's the
> snippet. I don't know if
> > this is all the information neccessary for someone
> to give an opinion,
> > so forgive me for my ignorance.
> >
> > ---------------------
> > SELECT d.destination, i.nights, (SELECT
> MIN(inside_bro) FROM sailings
> > WHERE i.itin_id = itin_id GROUP BY itin_id ORDER
> BY itin_id) AS
> > min_inside_bro
> >
> > FROM itineraries AS i, destinations AS d, ships AS
> s, cruise_lines AS
> > cl, sailings
> >
> > WHERE i.destination = d.dest_id AND i.cline =
> cl.cline_id AND i.ship =
> > s.ship_id
> >
> > GROUP BY i.itin_id
> >
> > ORDER BY destination, sailing_date, cl_name,
> ship_name, sailing_port
> > ---------------------
> >
> > Here is the error I get:
> > "#1064 - You have an error in your SQL syntax.
> Check the manual that
> > corresponds to your MySQL server version for the
> right syntax to use
> > near 'SELECT MIN(inside_bro) FROM sailings WHERE
> i.itin_id = itin_id"
> >
> > If any one has any idea about what the problem is,
> please let me know.
> > Again, I'm now at this.
> >
> > Thanks very much,
> >
> > Mark
> 
> 
> 
> 
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