I'd suggest using the following Javascript pop-up calendar! Its easy to 
use yet very flexible. I've used other Javascripts from this guy's site 
and they've worked VERY well. I highly recommend them. You can see demos 
of the pop-up calendar and download the code for free (he accepts 
donations) at http://www.mattkruse.com/javascript/calendarpopup/

Best regards,
Jim at iDimensionz.com
-- 
http://www.iDimensionz.com Professional web site design and affordable 
web site hosting.
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kab62uk wrote:

> Hi there I am a newbie so hope you guys can help. I am developing an
> admin panel for a charity who run courses for people who have been
> ill and are tryin to get back into work.
>
> I am struggling with the dates part of it. Originally I had a
> problem with getting the date to output to UK format and after much
> googling, I asked a techie friend, who suggested inputting the dates
> via 3 drop downs - day, month, year.
>
> This is fine via an html form, but I cant seem to work out the
> output.
>
>
> I can do something along the lines of: <td><?php echo
> $row_Recordset1['day']; ?>/<?php echo $row_Recordset1['month']; ?>/<?
> php echo $row_Recordset1['year']; ?></td>
> which will give me something like 01/01/2006
>
> but what I actually want is 1st January 2006
>
> I thought about perhaps getting the mysql database to read the three
> columns into one string in a fourth column 01012006, then setting
> the output something along the lines of:
>
> mysql_query("select *, DATE_FORMAT(date, '%d/%m/%Y') as editeddate
> from tablename");
> but how do I get it into one string in a fourth column???
> or:
> is there a better way to do it??
>
> I also th0ught about having a hidden field on the input form - so I
> have drop downs for day, month, and year in my input form which then
> add all three to the hidden field ( as a string) which then inputs
> to the mysaql database - and I could use the above DATE_FORMAT to
> convert to UK in the output page.
> Awful stuck here any help would be very much appreciated!
> Thank You




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