i saw ur code first of all see the correct code, and try it.
<?php
Session_start();
if ($_SESSION['auth'] != "yes")
{
echo "<p><a href=''>Login /
Signup</a></p>";
echo "<p><a href=''>Signout</a></p>";
exit();
}
?>
above is the correct that should be written.
here are the code errors in your code
1. @ should not be used with $_SESSION variables.
2. = !'yes' not correct, the correct code is !='yes'.
3. page should be saved as .php extention like abc.php, i think u r
using the php code in HTML page that's why it's not giving u any
output.
try above option, i m sure it will solve ur probs.
in case still u face any problem, i would live to see ur actual code
what is written on ur page.
BABAL
--- In [email protected], "jnoelcook" <[EMAIL PROTECTED]> wrote:
>
> All,
>
> I am a newbie to php, and have many questions.
>
> I am trying to create a link to appear on an HTML page that
> shows: "Login / Signup" when not logged in, and: "Signout" when one
> IS logged in.
>
> I placed the following lines of code in my HTML text in the place
> where I want the link to be.
>
> <?php
>
> if (@$_SESSION['auth'] = !"yes")
> {
> echo = "<p><a href=''>Login /
> Signup</a></p>";
> echo = "<p><a href=''>Signout</a></p>";
> exit();
> }
> ?>
>
> However, when I go to this page, no link whatsoever appears. Could
> someone provide the correct code for this command?
>
> Thanks much!!!
>
> Jeff
>
The php_mysql group is dedicated to learn more about the PHP/MySQL web database possibilities through group learning.
SPONSORED LINKS
| American general life and accident insurance company | American general life insurance company | American general life |
| American general mortgage | American general life insurance | Computer internet security |
YAHOO! GROUPS LINKS
- Visit your group "php_mysql" on the web.
- To unsubscribe from this group, send an email to:
[EMAIL PROTECTED]
- Your use of Yahoo! Groups is subject to the Yahoo! Terms of Service.
