Thank u
yes ur advice did help[:)]
Necromancer <[EMAIL PROTECTED]> wrote:
echo "<td> <form name="acceptform" method="post"
action="acceptrequest2.php">";
should be changed to :
echo "<td> <form name=\"acceptform\" method=\"post\" action=
\"acceptrequest2.php\">";
explanation :
you've choose to use "" (double quotes) instead '' (single quotes)
colaborated with your echo command.
as you can see, inside your "strings" there is double quotes characters.
you need to escaping those single quotes characters using \".
hope this can help
-Necro
On Wed, 2008-01-16 at 08:22 +0000, pratimadongare wrote:
>
> We need to display values from db in a table using php
> each row shd hv a column with a checkbox
> we tried the following code
>
> <?php
> mysql_connect("localhost", "root", "") or die(mysql_error());
> mysql_select_db("digital_lib") or die(mysql_error());
> echo 'connected';
>
> $query = "select * from employee where valid='0'";
> $result =mysql_query($query) or die(mysql_error());
> $num=mysql_numrows($result);
>
> echo $num."<br/><br/>";
>
> echo "<table border=1> \n";
> echo " <th>";
> echo " <td><b>employee id </b></td> \n ";
> echo " <td><b>library id </b></td> \n ";
> echo " <td><b>Employee name </b></td> \n ";
> echo " <td><b>Division</b></td> \n ";
> echo " <td><b>Designation</b></td> \n ";
> echo " <td><b>Email id</b></td> \n ";
> echo " </th> \n";
>
> $i=0;
> while ($i < $num) {
>
> $eid=mysql_result($result,$i,"empid");
> $lid=mysql_result($result,$i,"libid");
> $empname=mysql_result($result,$i,"ename");
> $div=mysql_result($result,$i,"division");
> $desig=mysql_result($result,$i,"designation");
> $email=mysql_result($result,$i,"emailid");
>
> echo " <tr> \n";
> echo "<td> <form name="acceptform" method="post"
> action="acceptrequest2.php">";
> echo "<input type="checkbox" name="selected"> </td>";
> echo " <td> $eid </td> \n";
> echo " <td> $lid </td> \n";
> echo " <td> $empname </td> \n";
> echo " <td> $div</td> \n";
> echo " <td> $desig </td> \n";
> echo " <td> $email</td> \n";
> echo " </tr> \n";
>
> $i++;
>
> }
> echo "</form>";
> echo "</table> \n";
>
> mysql_close();
> ?>
>
> error in the highlighted line is
>
> Parse error: parse error, unexpected T_STRING, expecting ',' or ';' in
> d:\Inetpub\wwwroot\sakec\acceptrequest1.php on line 34
>
> where r we going wrong?
>
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