ID: 20760
User updated by: [EMAIL PROTECTED]
Reported By: [EMAIL PROTECTED]
Status: Open
Bug Type: Documentation problem
Operating System: RedHat 8.0
PHP Version: 4.2.2
New Comment:
OK, but mark it in the documentation with a big red callsign. ;-)
But what I'm still interested in, is _why_ this is intended. The only
reason I can think of is to confuse other programmers, but that would
be absurd.
Previous Comments:
------------------------------------------------------------------------
[2002-12-02 04:29:18] [EMAIL PROTECTED]
This is indeed intended behavior, but it should be documented. I have
some logs about this, but can not find them now.
Derick
------------------------------------------------------------------------
[2002-12-02 04:24:24] [EMAIL PROTECTED]
We have found a strange behaviour regarding $this. One of our
programmers made a mistake during programming, which led to
"Heisenbugs", which were not quite easy to find and fix. We could
reduce the problem to a simple program to present it:
<?
class Foo {
var $bla;
function quux() {
$this->bla = 5;
}
}
class Bar {
var $bla;
function do_stuff() {
$this->bla = 10;
Foo::quux();
echo $this->bla;
}
}
$blabla = new Bar;
$blabla->do_stuff();
?>
The output is: "5"
Obviously, Bar::do_stuff() is not allowed to call Foo::quux() since
Foo::quux() is using $this. Now the strange thing comes: instead of
casting an error, PHP happily accepts the code. But the $this in
Foo::quux is the same $this as in Bar::do_stuff(), i.e. $blabla, and
that's why the output is 5. Is this behaviour intended? At least I
couldn't find it documented anywhere. IMO the user should be warned
when $this is used in a static function.
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=20760&edit=1
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