ID: 22342
Updated by: [EMAIL PROTECTED]
Reported By: peter-phpbug at dataloss dot nl
-Status: Bogus
+Status: Duplicate
Bug Type: Documentation problem
Operating System: Linux
PHP Version: 4.3.1
New Comment:
dup. of #15438
operator precedence problem: or is evaluated before require
i have to confess that the sample doesn't make sense for require, but
it is at least a documentation problem for include:
include("somefile") or die(...);
whereas
(include("somefile")) or die(...);
works as expected
IMHO the WTF factor here is rather big ... :(
Previous Comments:
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[2003-02-21 04:51:13] [EMAIL PROTECTED]
require() dies with fatal error if file is not found..
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[2003-02-20 18:14:23] peter-phpbug at dataloss dot nl
If one would use a line similar to
require("include/xhtml11.php") or die("argh!");
php will fail stating it cannot open "1".
The more intuitive result can be obtained by doing
(require("include/xhtml11.php")) or die("argh!");
I know that require or die is wrong, since require is not a function.
However, due to the way precedence (apparently) works with require, the
result is non-intuitive and confusing (I am assuming php is evaluating
'(..) or die(..)' to 'true', which is 1).
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