ID: 17386
Updated by: [EMAIL PROTECTED]
Reported By: m dot ford at lmu dot ac dot uk
-Status: Open
+Status: Closed
Bug Type: Documentation problem
PHP Version: 4.1.2
Assigned To: john
New Comment:
The precedence is also already documented by the sentence "Although !
has a higher precedence than =, PHP will still allow expressions
similar to the following: if (!$a = foo()), in which case the output
from foo() is put into $a."
Previous Comments:
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[2003-06-21 13:27:16] [EMAIL PROTECTED]
The document was updated and now describes the assignment operators
have right associativity. However I think the precedence rule is
another issue.
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[2002-11-28 18:49:00] [EMAIL PROTECTED]
I'll make the change for the associtivity from left to right, but I
don't know if I should just make a note of the example regarding
precedence rules.
Anyone know if its intended behavior, or should this have thrown a
parse error?
John
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[2002-05-23 09:34:04] m dot ford at lmu dot ac dot uk
The operators page at /manual/en/language.operators.php lists the the
assignment operators (=, +=, etc.) as being left associative, but they
must logically be right associative. Left associativity would mean that
this:
$a = $b = 0;
was interpreted as:
($a = $b) =0;
which is clearly nonsensical. Indeed a quick test shows that:
$d = $c += $a += $b += 4;
is interpreted as:
$d = ($c += ($a += ($b += 4)));
which looks like right associativity to me!
(Actually, a little further testing suggests that the assignment
operators need some special annotations, as they don't appear to
strictly obey their stated precedence level. For example, the
statement:
$x = $z + $y = 543;
if interpreted strictly according to the precedence rules should be
equivalent to:
$x = ($z + $y) = 543;
which would be a parse error, but in fact is interpreted as:
$x = $z + ($y = 543);
which may be the "obvious" intention, but had me WTF-ing for a while!!)
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Edit this bug report at http://bugs.php.net/?id=17386&edit=1