ID: 37776
User updated by: karibu at gmx dot net
Reported By: karibu at gmx dot net
Status: Open
Bug Type: Documentation problem
Operating System: MacOS X, MorphOS
PHP Version: Irrelevant
New Comment:
same happens w/o the exit too.
anyway... of course I expect a different result in that case. It's very
confusing for (e.g.) c programmers where that works just fine:
int main(void)
{
printfoobar();
return 0;
}
#define FOO "bar"
void printfoobar()
{
printf(FOO);
}
So it should be documented IMHO... a small extra sentence in the
documentation doesn't hurt.. I think ;)
Previous Comments:
------------------------------------------------------------------------
[2006-06-10 23:27:16] [EMAIL PROTECTED]
Would you expect this to work different somehow?
<?php
printfoobar();
exit;
$FOO = 'bar');
function printfoobar()
{
echo $GLOBALS["FOO"];
}
?>
I would not. Not only did you call the function before the define, but
you exit() before the define. There is no way that is getting defined.
------------------------------------------------------------------------
[2006-06-10 23:12:17] karibu at gmx dot net
Description:
------------
When I *call* a function which uses a define before this define is
actually defined in the source it appears in the function to be
undefined.
I didn't found this behavoir documented (not in the english or german
section) but it would probably very useful as it quickly can lead to
unexpected problems w/o instantly possible to detect why (in a script
of mine it caused busylooping f.ex.).
Reproduce code:
---------------
<?php
printfoobar();
exit;
define(FOO, 'bar');
function printfoobar()
{
echo FOO;
}
?>
Expected result:
----------------
bar
Actual result:
--------------
FOO
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=37776&edit=1
