Hannes Magnusson wrote:
On Sat, Nov 21, 2009 at 02:12, Hannes Magnusson
<hannes.magnus...@gmail.com> wrote:
On Tue, Nov 17, 2009 at 18:31, Daniel Veillard <veill...@redhat.com> wrote:
On Tue, Nov 17, 2009 at 05:03:41PM +0100, Murray Cumming wrote:
On Tue, 2009-11-17 at 14:24 +0100, Daniel Veillard wrote:
On Tue, Nov 17, 2009 at 01:33:44PM +0100, Murray Cumming wrote:
Should I be able to validate an XML document (such as a .glade file)
that has no DOCTYPE line, and therefore doesn't specify a DTD?
When I try it with xmllint, I get this error
validity error : Validation failed: no DTD found !
even when I have specified a local DTD with --dtdvalid.
Works for me with the version from git head:
Thanks. I was actually using
xmllint --valid --dtdvalid mydtd.dtd mydoc.xml
So is --dtdvalid an alternative to --valid rather than a way of using
--valid?
and alternative, as DTD validation as defined in the XML-1.0 spec
is --valid i.e. validating as parsing based on DOCTYPE contained in
the document, and --dtdvalid is just a different kind of validation
closely related, but certainly different, and in subtle case you may
see different results (but in general it will be the same !)
I did not know that.
This doesn't however seem to be implemented in PHP, Rob... :)
Is this something we can implement? Pretty-please? :)
AFAICT it could help us _massively_ when rendering "standalone
extension" (and possibly per-file) in the documentations.
The "root file" (manua.xml) could still have the DTD attached, but
when rendering a standalone book (extension/reference) we could simply
attach the DTD via "dtdvalid" to get the entities defined in the DTD
(all our snippets) and validate it.
Actually, I just tried it with xmllint.
--dtdvalid doesn't inject the referenced dtd into the doc so entities
aren't "copied over", its pure validation against the dtd :(
Rob: You wouldn't happen to know of any neat "workarounds" for that?
I'll take a look at this today. Should have some free time this afternoon.
Rob
