Hello,
I try to get a grasp, how to use Pilog properly. As I thought it
resembles Prolog but only with a Lisp-ish syntax, I tried to implement
the both Prolog rules for member/2 and append/3 in Pilog. But I guess, I
did not really understand Pilog properly, as I cannot get the
definitions to work correctly.
The Prolog definitions are:
member(X, [X|_]).
member(X, [_|T]) :- member(X, T).
append([], L, L).
append([H|L1], L2, [H|L3]) :- append(L1, L2, L3).
I already fail defining a correct Pilog member. This is, what I already got:
(be mymember (@ NIL) T)
(be mymember (@X @L) (equal (-> @X) (car (-> @L))))
(be mymember (@X @L) (mymember @X (cdr (-> @L))))
But if I try, for instance, (prove (goal '((mymember '2 '(1 2 3)))))
it seems to run forever ...
Can someone please shed some light on my, how to define member/2 and
append/3 in Pilog properly?
Thanks in advance ...
Ciao,
Cle.
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