That does the trick.  Thank you Alex!

I think Haskell makes a big deal about Pattern Matching.  I'm using your 
"match" here as a simple string matcher.  I'm sure there are better ways, but 
I'm happy with my baby steps that appear to work!

Happy 2017.

On Tue, Jan 03, 2017 at 10:21:38AM +0100, Alexander Burger wrote:
On Tue, Jan 03, 2017 at 07:52:34AM +0100, Alexander Burger wrote:
   (match (append '(@A) (chop Varstring) '(@B)) ...

BTW, better is perhaps

  (match (cons '@A (conc (chop Varstring) '(@B))) ...

because 'append' unnecessarily copies the list just built by 'chop'.
'conc' avoids that garbage. Not critical though ;)

♪♫ Alex
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