On Mon, Feb 06, 2017 at 12:25:14PM +0100, Alexander Burger wrote:
> > I'd like to split a list '(txt1 2 txt2 6....
> > into 2 lists
> > '(txt1 txt2...
> > and
> > '(2 6
> 
> You could for example filter them:
> 
>    (let
>       (Lst '(txt1 2 txt2 6)
>          A (filter sym? Lst)
>          B (filter num? Lst) )
>       ... use A and B ...)

It is not clear what you need.


If, for example, you want every *second* element, there is a nice trick:

   : (filter prog2 (1 a 2 b 3 c) '(T NIL .))
   -> (1 2 3)

   : (filter prog2 (1 a 2 b 3 c) '(NIL T .))
   -> (a b c)

Similarly, you can extract other sequences if you pass the right pattern of
NIL's and T's.

♪♫ Alex
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