Hi everybody, thanks again for the responses. I am really obtaining many
ideas (:

About the depth of my data, yeah I am only looking for connected components
of depth three which I think will be a great help because my BFS would be
limited in the number of iterations.

And about the example I must have these records x -> y, y -> z and z -> x in
order to output the x, y, z result record. But there can probably be
elements who do not close the graph. For example, I might have a record like
x -> b, and b doesn't references nobody, so I would have to ignore it. Is
that what you meant Tanton?
What about a self-join three times?Would that be a bad idea?
Thanks again.

Renato M.

2010/6/11 Dmitriy Ryaboy <[email protected]>

> hc, self-join should just work, but if it doesn't:
>
> split table into table_2 if 1==1, table3 if 1==1;
>
> OR
>
> table_2 = foreach table generate *;
> table3 = foreach table generate *;
>
> AND THEN
>
> T = join table by id1, table_2 by id2, table_3 by id3
>
> -D
>
> On Fri, Jun 11, 2010 at 10:59 AM, hc busy <[email protected]> wrote:
>
> > Yeah, that IS hard in pig. I'm not even sure how to do a self-join in
> Pig.
> > Like you can't really say
> >
> > T = join Table by id1, Table by id2, Table by id3;
> >
> > I think PigLatin will complain that it's confused which Table is and
> which
> > id1 goes with which table.
> >
> > I had been proposing that we allow PigLatin to allow recursive functions,
> > that way we can do loops. But recursive functions doesn't fit in the
> > data-flow language paradigm.
> >
> > But I think people have offered many alternatives in terms of scripting
> > language that can wrap PigLatin that has loop and flow control
> constructs.
> >
> >
> > On Thu, Jun 10, 2010 at 9:55 PM, Tanton Gibbs <[email protected]
> > >wrote:
> >
> > > It really depends on the depth of your graph.  Are you only dealing
> > > with connected components of depth 3 or could they be deeper.
> > >
> > > For instance, can you have x -> y, y -> z, and z -> a?  If so, do you
> > > need your record to be x, y, z, a?  Or, are you guaranteed that it
> > > will always be x -> z and y -> z?
> > >
> > > I really need more information about your data before I can offer too
> > > much advice.
> > >
> > > On Thu, Jun 10, 2010 at 5:38 PM, Renato Marroquín Mogrovejo
> > > <[email protected]> wrote:
> > > > Hi everybody, thanks a lot for your responses.
> > > >
> > > > I am actually not looking for a transitive closure, I am not trying
> to
> > > > "infer" that given *x -> y* and *y -> z*, then *x -> z *(@hc.busy:
> that
> > > is
> > > > in short terms a transitive closure ^^)  because I have the data that
> > > proves
> > > > it. And yeah I am aware of first logic expressive power, but maybe I
> > will
> > > > think about giving an inference engine a try some time in the future.
> > > >
> > > > I am actually looking at a connected graph-like problem. The sample
> > > records
> > > > resemble a bidirectional triangle.
> > > >
> > > >            990201
> > > >         /              \
> > > >        /                \
> > > >       /                  \
> > > >      /                    \
> > > > 770011  ------- 770083
> > > >
> > > > I tried using a smaller version of the problem by using SQL and got a
> > > > horribly huge query which is a non-scalable possibility for me. I
> have
> > > over
> > > > 500Gbs in structured files. I used a triple join but I had to
> retrieve
> > > all
> > > > existing possibilities.
> > > > So that is why I thought on using something like Hc.busy mentioned.
> > > >
> > > > Queries: idx1, idx2, sc, va, p1, p2
> > > > possibilities: possibs = foreach queries generate idx1, flatten(a
> > triple
> > > > self join of the data)
> > > >
> > > > and by using the flattening command, get all possible combinations,
> but
> > I
> > > am
> > > > not sure that would be the correct approach. Anyhow I thought maybe
> > > > performing some breadth first search but that would give me an
> > algorithm
> > > > O(n2)  so  )=
> > > > Hey Tanton how would you implement and use an union-find structure?
> Do
> > > you
> > > > think it is possible with PIG?
> > > >
> > > > Thanks again.
> > > >
> > > >
> > > > 2010/6/10 Tanton Gibbs <[email protected]>
> > > >
> > > >> To be specific, he's looking for connected components in the graph.
> > > >>
> > > >> It's not overly easy to do in an ETL tool (or in pig), but if you
> can
> > > >> wrap the script in a loop it is possible.
> > > >>
> > > >> There are actually some really interesting parallel algorithms for
> > > >> finding connected components.  If you know you are only going to
> have
> > > >> two keys, it is a bit simpler to code (but not any more efficient).
> > > >> Essentially, you can implement your union-find algorithm as a series
> > > >> of sorts and merges, which on a large parallel system is actually
> > > >> quite fast.
> > > >>
> > > >> Tanton
> > > >>
> > > >> On Thu, Jun 10, 2010 at 3:33 PM, hc busy <[email protected]> wrote:
> > > >> > What's a transitive closure?
> > > >> >
> > > >> > On Thu, Jun 10, 2010 at 2:34 PM, Gianmarco <
> [email protected]
> > >
> > > >> wrote:
> > > >> >
> > > >> >> I think what he wants is a transitive closure of the relation,
> > which
> > > >> >> is not achievable in SQL-like languages alone (first order logic
> > > >> >> expressive power).
> > > >> >> I suppose Pig Latin falls in this category.
> > > >> >>
> > > >> >>
> > > >> >> -- Gianmarco
> > > >> >>
> > > >> >> On Thu, Jun 10, 2010 at 19:54, hc busy <[email protected]>
> wrote:
> > > >> >> > Is this like a tricky interview question? I don't see the
> pattern
> > > >> between
> > > >> >> > those three numbers you listed and the sample of the table.
> > > >> >> >
> > > >> >> > 770011 770083 524 1e-120 89 12
> > > >> >> > 770083 770011 494 1e-120 39 100
> > > >> >> >
> > > >> >> > ahh, I guess these are related because id1=id2 an id2=id1...
> > Here's
> > > a
> > > >> >> first
> > > >> >> > pass at the problem. Project:
> > > >> >> >
> > > >> >> > P1 = foreach table generate id1 as id1, id2 as id2, *;
> > > >> >> > P2 = foreach table generate id2 as id1, id1 as id2, *;
> > > >> >> > J = join P1 by (id1, id2), P2 by (id1,id2);
> > > >> >> >
> > > >> >> > and now J contains pairs of rows from original table where id1
> > and
> > > id2
> > > >> >> are
> > > >> >> > reversed.
> > > >> >> >
> > > >> >> > is this what you want?
> > > >> >> >
> > > >> >> > On Wed, Jun 9, 2010 at 6:54 PM, Renato Marroquín Mogrovejo <
> > > >> >> > [email protected]> wrote:
> > > >> >> >
> > > >> >> >> Hi everyone, today I came across with a particular query that
> I
> > > don't
> > > >> >> know
> > > >> >> >> how to model in PIG. Part of my data looks like this:
> > > >> >> >>
> > > >> >> >> Id1 Id2 Sc Va P1 P2
> > > >> >> >> --------- --------- ----- --------- ----- ----
> > > >> >> >> 770011 990201 401 1e-125 100 65
> > > >> >> >> 990201 770011 440 1e-125 100 42
> > > >> >> >> 770011 770083 524 1e-120 89 12
> > > >> >> >> 770083 770011 494 1e-120 39 100
> > > >> >> >> 990201 770083 341 1e-125 73 41
> > > >> >> >> 770083 990201 421 1e-125 90 85
> > > >> >> >> .
> > > >> >> >> .
> > > >> >> >> .
> > > >> >> >>
> > > >> >> >> what I would like to retrieve is something like
> > > >> >> >> this:                                             770011
> 990201
> > > >> 770083
> > > >> >> >> because they are records actually related.
> > > >> >> >> Any kind of ideas are highly appreciated. Thanks in advanced.
> > > >> >> >>
> > > >> >> >> Renato M.
> > > >> >> >>
> > > >> >> >
> > > >> >>
> > > >> >
> > > >>
> > > >
> > >
> >
>

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