Am Montag, den 25.07.2016, 15:56 +0200 schrieb Jaromír Mikeš: > I will pass this question to upstream.
This question was rhetoric, it won't fit. You have 8 bytes in the buffer, two of them are used by " L" or " R", respectively, and another one for the '\0' delimiter. This means 5 bytes are left for the floating point number, of which one is the decimal dot. That it, you must delimit the floating point formater to something like "%3.1f" for it to fit into the string buffer. Or, given that upstream apparently intended to output integers, maybe "%5.0f". - Fabian
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