Hi Alan,
that is most definitely possible:
function range( n )
integer :: n
real(plflt), dimension(n) :: range
range = (/ (i, i=1,n) /)
end function range
I will introduce that function and maybe some others as well.
Regards,
Arjen
On 2011-10-26 10:19, Alan W. Irwin wrote:
>
> One suggestion is to change that first statement to the cleaner looking
>
> x = 3.6_plflt * range
>
>
> where you declare at the start of plot3 (subject to my shaky Fortran 95
> syntax)
>
> integer, parameter :: md = 101
> real(plflt), dimension(1:md) :: range=(/(j,j=0,md-1)/), x, y
>
> I take my inspiration from examples/python/xw01.py where we have
>
> x = 3.6*arange(101)
> y = sin((pi/180.)*x)
>
Is that idea
> possible or is Fortran 95 fundamentally more limited than numpy in
> this regard?
>
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