From: Paul Mooring <[email protected]> > This is probably a really obvious question but how can I match > everything up to a character not including that character with regex? > For example: > [email protected] => person > [email protected] => me
#!/usr/bin/perl -w $a="[email protected]"; $a=~m/^(.*)\@/; $b=$1; print "a= $a\n"; print "b= $b\n"; You may have to modify the regex and the structures for non-Perl languages since @ is a special char in Perl and may not be in others. The regex here matches everything from the beginning of the string up to the first @, not including the @, and puts it in $1 or \1 (first backreference). But if this was all I wanted, I might use a substr instead of a regex, since regexes are a bit more complex than what you said you wanted. (Don't use a .50 to shoot a chipmunk, etcetera....) -- Matt G / Dances With Crows The Crow202 Blog: http://crow202.org/wordpress/ There is no Darkness in Eternity/But only Light too dim for us to see --------------------------------------------------- PLUG-discuss mailing list - [email protected] To subscribe, unsubscribe, or to change your mail settings: http://lists.PLUG.phoenix.az.us/mailman/listinfo/plug-discuss
