Another way would be
if ($vaidateStr == preg_replace("/[^a-z0-9\-]/i", "", $vaidateStr)) {
/true, or valid...
}
the "i" after the last / makes it case insensitive. So it should match
upper and lower alpha characters.
Ah yes, I also forgot the uppercase chars
if ($vaidateStr == preg_replace("/[^a-zA-Z0-9\-]/", "", $vaidateStr)) {
/true, or valid...
}
BTW also as Eric says, the carrot (^) inside the square brackets means
"anything but" (negation), thus how this works..
Ben
On Wed, Jul 20, 2011 at 9:38 PM, Eric Cope <[email protected]
<mailto:[email protected]>> wrote:
Here is the regular expression:
/^[a-zA-Z0-9\-]+$/
the ^ requires the pattern match at the beginning of the string.
The + requires at least one of these characters, but no upper limit.
You can use * if you don't need the lower limit of 1.
$ requires the patten match all the way to the end of the string.
The dash requires escaping, hence the back slash.
http://www.regular-expressions.info/anchors.html
Thanks,
Eric
On Wed, Jul 20, 2011 at 8:34 PM, keith smith <[email protected]
<mailto:[email protected]>> wrote:
Hi,
I have an input string that should only be lower or upper
alphas, numbers and can contain a hyphen.
I'm trying to figure out how to get PHP preg_match to verify the
input string only contains these chars.
I tried some thing like this and it always returns true if I
have one or more of the specified chars, even if I have a char
that is not specified.
I need a true for any string that contains Alphas and/or numbers
and/or one or more hyphens. I need it to return if the string
contains anything else.
preg_match("/[a-z0-9\+\-]/", $vaidateStr)
I do not need to use preg_match, I'm looking for a simple solution.
Any pointers are much appreciated.
------------------------
Keith Smith
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---
Ben
/print ''.join(map(lambda x: chr(x), ( (ord('a')-(3*5)),
int(math.sqrt(math.pi*76)*5+2), int(math.ceil(math.e)*28),
int(math.floor(math.e)*35), long(abs(4%3*35+3)*2))))/
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