Having the natural log of 0 might be an issue. I'm pretty sure that the natural log of 0 would be negative infinity. That would likely not produce a straight line graph....
Just have two extra rows where you do your computations. ( =LN(A1) and =1/B1 ) for example. Then just copy and paste and it will give you your whole series. Then make the chart from those pre-computed values. (But isn't a vapor pressure of 0 a vacuum? Is it not 1 for something at equilibrium in a lab environment? I could be really misremembering, of course.) On Sun, Feb 14, 2010 at 4:32 PM, Michael Robinson <[email protected]> wrote: > I have temperature values in Kelvin corresponding to vapor pressure > values in kPa's. I need to graph natural_log(vapor pressure) as Y > and (1/temperature) for the X axis. How do I do this in Openoffice > Calc??? I should end up with a straight line, but I probably won't. > > A problem is that my initial vapor pressure is 0, no ethanol in the > sealed container. I don't think the natural_log(0) is defined. > > _______________________________________________ > PLUG mailing list > [email protected] > http://lists.pdxlinux.org/mailman/listinfo/plug > _______________________________________________ PLUG mailing list [email protected] http://lists.pdxlinux.org/mailman/listinfo/plug
