I'm not completely clear on what you're trying to accomplish, so forgive me if I'm off base with these, but here are a couple of thoughts...
As far as I know, cut cannot deal with multiple delimiters... nor can it handle a single delimiter consisting of multiple characters. `ls -1` (that's a "one", not an "L") will give you a listing of just the file names, each on a separate line If you are trying to pull out more fields than just the filenames, try using `cut -c8-12,25-` (replacing the numbers with the appropriate values)... this example will give you chars 8 through 12 and 25 through the end of each line. If using `ls -l`, the fields are fixed-length (other than file name, but that is the last field), so this should be useful. Perhaps more usefulness can be gotten out of this by using some of the formatting and other options for the ls command. Hope something here helps, Rick On Mon, Jun 11, 2012 at 8:23 AM, Rich Shepard <[email protected]>wrote: > On Mon, 11 Jun 2012, Chris Berry wrote: > > > I would generally use awk to do that, something like this: > > ls -alh | awk '{print $9 }' > > Chris, > > I thought of that but figured cut would be the better way. Apparenly not. > > Thanks, > > Rich > > _______________________________________________ > PLUG mailing list > [email protected] > http://lists.pdxlinux.org/mailman/listinfo/plug > _______________________________________________ PLUG mailing list [email protected] http://lists.pdxlinux.org/mailman/listinfo/plug
