AFAICR (As far as I can remember) from my EE subjects, the 1.414 is
needed because the computation (for 115V and 0.3amps) involves
alternating current (AC).  P=VI is okay for DC computations. 

sherwin-plug wrote:
> 
> [EMAIL PROTECTED] writes:
> >These figures were determined by the following formula: Watts =
> >(amps)(volts) / 1.414, given that the average computer (for this test, a
> >Pentium-III 450 MHz) draws 0.3 amps at 115 volts.
> 
> AFAIK  the formula for power is
> P=VI or P=(I^2)/R where P is in
> watts, V in volts, I in amps and R in ohms.
> 
> Where did 1.414 come from?
> Just a thought. :-)
> 
> sherwin
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