kindly give me the configuration procedure for sendmail !!!
thanks,
lyndon
On Monday 16 December 2002 14:16, Gerald Timothy Quimpo wrote:
> On Sunday 15 December 2002 11:45 pm, Ina Patricia Lopez wrote:
> > what command i can use to convert the last change field (/etc/shadow)
> > to date format?
>
> man shadow (on mandrake, not sure if you have that on your installation)
> says that the last password change field is the number of days since
> 1Jan1970 since the password was changed. so if it is "1", then
> the password was last changed on 2 Jan 1970.
>
> i don't know what the quick solution would be offhand. so a hack would be:
> use "man 3 mktime" to create a date corresponding to 1 Jan 1970.
> take the last change field. multiple by 3600*24 (number of seconds per
> day). the number you get is the number of seconds since 1 Jan 1970.
> add that number to the number you got from running mktime.
> call localtime to get the mm/dd/yy.
>
> NOTE: i have not exhaustively tested. but one or two tests indicate
> that this is OK (watch out for whenever it is that longs as seconds from
> 1/1/1970 roll over, sometime in 2038).
>
> #include <time.h>
> #include <stdio.h>
> int main(int argc, char **argv)
> {
> int nd=11957; /* hardcoded, value from last changed in /etc/shadow */
> struct tm tm;
> time_t zero;
>
> tm.tm_sec=32; /* random number less than 60 */
> tm.tm_min=32; /* ditto */
> tm.tm_hour=1; /* first hour of the first day of the month */
> tm.tm_mday=1;
> tm.tm_mon=1;
> tm.tm_year=1970;
> /* tm now contains Jan 1 1970 1:32:32 */
> zero=mktime(&tm);
> zero+=(3600*24*nd);
> printf("%s\n",ctime(&zero)); /* prints the date that nd corresponds to */
> }
>
>
> tiger
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