... and to negate the conditional use an exclamation point (!) :
$ echo -e "a\tb\tc\td\na\tb\t\td" | awk -F'\t' '$3 != "" {print}'
a b c d
Regards,
- Robert
On Sat, Oct 30, 2021 at 9:46 AM Robert Citek <robert.ci...@gmail.com> wrote:
> Sorry, this item didn't get pasted in my last post:
>
> $ echo -e "a\tb\tc\td\na\tb\t\td" | awk '{print $1" = "$2" = "$3" = "$4}'
> a = b = c = d
> a = b = d =
>
> Notice that you have to specify the field separator with the -F option,
> otherwise awk compresses consecutive whitespace characters by default.
>
> Regards,
> - Robert
>
> On Sat, Oct 30, 2021 at 9:41 AM Robert Citek <robert.ci...@gmail.com>
> wrote:
>
>> Hello Rich,
>>
>> Here's a sample:
>>
>> $ echo -e "a\tb\tc\td\na\tb\t\td" | awk -F'\t' '{print}'
>> a b c d
>> a b d
>>
>> $ echo -e "a\tb\tc\td\na\tb\t\td" | awk -F'\t' '$3=="" {print}'
>> a b d
>>
>> Good luck and let us know how it goes.
>>
>> Regards,
>> - Robert
>>
>> On Sat, Oct 30, 2021 at 9:31 AM Rich Shepard <rshep...@appl-ecosys.com>
>> wrote:
>>
>>> I've a 351K line file with 8 fields. About 50K of those lines has $8
>>> blank.
>>> I want awk to print only rows with values in all 8 fields. I'm not
>>> finding
>>> how to tell awk to print $0 if $8 is not blank.
>>>
>>> My awk/sed book doesn't seem to have this information and my web searches
>>> aren't finding the answer, either.
>>>
>>> Clue needed.
>>>
>>> Rich
>>>
>>
