I used 'extern "C"' in C++ code to include the header file of C, and declare
the variable in the header file, such as 'extern char g_switch'. And define
the variable in the correspond .c file, such as 'char g_swith = 1'. Now I
will access this variable from a C++ file/function. But I got a
un-initialized value from g_swith variable.
Why?
From: Corey Edwards <[EMAIL PROTECTED]>
Reply-To: Provo Linux Users Group Mailing List <[email protected]>
To: [email protected]
Subject: Re: c++ function can not call c routine or access c
globalvariable. Why?
Date: Thu, 23 Mar 2006 18:20:38 -0700
On Fri, 2006-03-24 at 09:07 +0800, Laurent R wrote:
> Yes, I compiled both parts of codes with the same compiler. But I did
not
> use extern "c" definition.
C and C++ link objects differently. By specifying 'extern "C"' you tell
the C++ compiler to use the C-style for the specified objects. C++ by
default will mangle the name to allow fancy things like overloading and
namespaces.
Corey
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