Stuart Jansen wrote: > Because echo is merely processing its argv and the '\0' is seen as > terminating the arg, not part of the arg.
So the shell is parsing the $'\x' and turning it into a binary blob for echo? That makes sense. --Dave /* PLUG: http://plug.org, #utah on irc.freenode.net Unsubscribe: http://plug.org/mailman/options/plug Don't fear the penguin. */
