Got the answer from a friend who doen't know any sql to speak of.  He does all his queries in Design view with Access.
 
SELECT NewMessage.MessageFrom, NewMessage.NewMessageText, NewMessage.MessageDate, NewMessage.MessageStatus, PlumUser.FirstName, PlumUser.LastName, NewMessage.MessageSentTo, PlumUser_1.FirstName, PlumUser_1.LastName, NewMessage.NewMessageText
FROM PlumUser AS PlumUser_1 INNER JOIN (PlumUser INNER JOIN NewMessage ON PlumUser.UserID = NewMessage.MessageFrom) ON PlumUser_1.UserID = NewMessage.MessageSentTo
WHERE (((NewMessage.MessageSentTo)=[enter user Id]));
 
I still don't quite know what that says.  Interestingly enough, the newMessage table is not in the FROM clause directly at all.  I hope after studying it to be able to figure it out and write it in the future with a more discriptive alias.
 
Thanks John and Bob (Bob sent me an email directly 'cause he could not post to the list),
 
Mark
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]On Behalf Of Saeed T. Richardson
Sent: Thursday, July 28, 2005 4:44 PM
To: [email protected]
Subject: Re: [plum] Custom Query for Two Plum Users

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I joined up too about 3 months ago. They've got me out of three really tough stumps - highly recommended.)

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plaudits and salutations,--

.................................................

saeed t. richardson, computer project manager

duke university school of medicine

post office box 3710 durham, north carolina 27710

tel: 919.684.2985; toll: 877.684.2985; fax: 919.668.3714


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On Jul 28, 2005, at 3:53 PM, Mark Fuqua wrote:

John,

I am stumped (which seems to becoming a normal state). So I joined
www.experts-exchange.com and posted the question. I think it was you who
recommended that site. Anyway, I'll let you know what happens.

Thanks,

Mark

-----Original Message-----
[mailto:[EMAIL PROTECTED]]On Behalf Of John
Stanley
Sent: Thursday, July 28, 2005 2:22 PM
Subject: RE: [plum] Custom Query for Two Plum Users


Mark, sorry about the missing plus signs, that was a syntax error on my
part.

have you tried this? (keep in mind that I know jack squat about access
except that it is finiky):

you should still be able to use table aliases (although I could be wrong
there). there were also spaces in front of PU and NewMessage that I removed,
but i dont know if that matters.

SELECT NewMessage.NewMessageId, NewMessage.NewMessageText,
PU2.FirstName + ' ' + PU2.LastName as 'messageFrom', PU.FirstName + ' ' +
PU.LastName as 'messagesentTo', NewMessage.MessageDate,
NewMessage.MessageStatus
FROM NewMessage
INNER JOIN PlumUser PU on ([PU].[UserID] =[NewMessage].[MessageSentTo])
INNER JOIN PlumUser PU2 on ([PU2].[UserID] = [NewMessage].[MessageFrom])



-----Original Message-----
From: Mark Fuqua [mailto:[EMAIL PROTECTED]]
Sent: Thursday, July 28, 2005 2:12 PM
Subject: RE: [plum] Custom Query for Two Plum Users


Hey John,

It sure looks like it will work, however I can't seem to get it to. I am
using Access2000 which has some peculiarities. The first items it didn't
like were the lack of + signs between the '' and LastName Fields. Fixed
that. Then it was the JOIN.

Seems Access likes INNERJOIN. After studying what you wrote and looking at
the lame Access help, this is where I am:

SELECT NewMessage.NewMessageId, NewMessage.NewMessageText,
PU2.FirstName + ' ' + PU2.LastName as 'messageFrom', PU.FirstName + ' ' +
PU.LastName as 'messagesentTo', NewMessage.MessageDate,
NewMessage.MessageStatus
FROM NewMessage
INNER JOIN PlumUser PU on([ PU].[UserID] =[ NewMessage].[MessageSentTo])
AND PlumUser PU2 on ([PU2].[UserID] = [NewMessage].[MessageFrom]);

The error message I have now is "syntax error in join statement" and it
highlights the PU inside the brackets.

Is it possible to just remove the PU and PU2? Or is it necessary for the
SELECT to know which "firstName" goes with which field?

Thanks John, below I copied the section in the Access help for inner join.




INNER JOIN Operation
Combines records from two tables whenever there are matching values in a
common field.

Syntax
FROM table1 INNER JOIN table2 ON table1.field1 compopr table2.field2

The INNER JOIN operation has these parts:

Part Description
table1, table2 The names of the tables from which records are combined.
field1, field2 The names of the fields that are joined. If they are not
numeric, the fields must be of the same data type and contain the same kind
of data, but they do not have to have the same name.
compopr Any relational comparison operator: "=," "<," ">," "<=," ">=," or
"<>."


Remarks
You can use an INNER JOIN operation in any FROM clause. This is the most
common type of join. Inner joins combine records from two tables whenever
there are matching values in a field common to both tables.

You can use INNER JOIN with the Departments and Employees tables to select
all the employees in each department. In contrast, to select all departments
(even if some have no employees assigned to them) or all employees (even if
some are not assigned to a department), you can use a LEFT JOIN or RIGHT
JOIN operation to create an outer join.

If you try to join fields containing Memo or OLE Object data, an error
occurs.

You can join any two numeric fields of like types. For example, you can join
on AutoNumber and Long fields because they are like types. However, you
cannot join Single and Double types of fields.

The following example shows how you could join the Categories and Products
tables on the CategoryID field:

SELECT CategoryName, ProductName

FROM Categories INNER JOIN Products

ON Categories.CategoryID = Products.CategoryID;


In the preceding example, CategoryID is the joined field, but it is not
included in the query output because it is not included in the SELECT
statement. To include the joined field, include the field name in the SELECT
statement - in this case, Categories.CategoryID.

You can also link several ON clauses in a JOIN statement, using the
following syntax:

SELECT fields
FROM table1 INNER JOIN table2
ON table1.field1 compopr table2.field1 AND
ON table1.field2 compopr table2.field2) OR
ON table1.field3 compopr table2.field3)];

You can also nest JOIN statements using the following syntax:

SELECT fields
FROM table1 INNER JOIN
(table2 INNER JOIN [( ]table3
[INNER JOIN [( ]tablex [INNER JOIN ...)]
ON table3.field3 compopr tablex.fieldx)]
ON table2.field2 compopr table3.field3)
ON table1.field1 compopr table2.field2;

A LEFT JOIN or a RIGHT JOIN may be nested inside an INNER JOIN, but an INNER
JOIN may not be nested inside a LEFT JOIN or a RIGHT JOIN.

See Also
FROM Clause (Microsoft Jet SQL) TRANSFORM Statement (Microsoft Jet SQL)
LEFT JOIN, RIGHT JOIN Operations (Microsoft Jet SQL) UNION Operation
(Microsoft Jet SQL)
SELECT Statement (Microsoft Jet SQL)


Example
INNER JOIN Operation Example


-----Original Message-----
[mailto:[EMAIL PROTECTED]]On Behalf Of John
Stanley
Sent: Thursday, July 28, 2005 12:45 PM
Subject: RE: [plum] Custom Query for Two Plum Users


How does this work?

SELECT NewMessage.NewMessageId, NewMessage.NewMessageText,
PU2.FirstName + ' ' PU2.LastName as 'messageFrom', PU.FirstName + ' '
PU.LastName as 'messagesentTo', NewMessage.MessageDate,
NewMessage.MessageStatus
FROM NewMessage
join PlumUser PU on PU.UserID = NewMessage.MessageSentTo
join PlumUser PU2 on PU2.UserID = NewMessage.MessageFrom




-----Original Message-----
From: Mark Fuqua [mailto:[EMAIL PROTECTED]]
Sent: Thursday, July 28, 2005 12:36 PM
Subject: [plum] Custom Query for Two Plum Users


Good afternoon,

I have a table called NewMessages which has two references to the Plum Users
table. I have been trying to write a query (at this point anyway) to just
return what is in the NewMessage table. What follows doen't work. Any idea
what will?

SELECT NewMessage.NewMessageId, NewMessage.NewMessageText,
NewMessage.MessageFrom, NewMessage.MessageSentTo, NewMessage.MessageDate,
NewMessage.MessageStatus
FROM PlumUser AS PlumUser1, PlumUser INNER JOIN NewMessage ON
(PlumUser.UserID = NewMessage.MessageSentTo) AND (PlumUser.UserID =
NewMessage.MessageFrom);

Actually, I would like to have the FirstName and LastName AS Name for both
references as well. But thought I should try and get it to work with just
ID first. But since I am obviously stumped with the easy one and have to
ask anyway, I thought... "why not go for all the marbles?"

Thanks,

Mark



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