Hi,
It's been a while since I've put on my programmer's hat, but I seem
to remember some weirdness with streams and functions like this. I
know it's a kludge, but if you create a var and assign read()'s value
to the var and then output the var to cout does it work?
Paul
On 11 Nov 2005, at 19:49, dan wrote:
I'm trying to read a pixel value from an image and output it to the
console, using
std::cout << read(25, 56);
Should this work? When compiling I get the error message:
main.c: In function 'int main()':
main.c:38: error: invalid conversion from 'int' to 'void*'
/usr/include/unistd.h:312: error: too few arguments to function
'ssize_t read(int, void*, size_t)'
main.c:38: error: at this point in file
make: *** [main] Error 1
If I remove that single piece of code, it compiles and functions fine
(its modified from the burro example).
--
http://www.danicity.co.uk
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